exam 1 review

site/posts/differential-quiz-2.html

@@ -1,5 +1,8 @@
 [!]
 [=post-]
+<p>
+    <i>This post is part of a series; you can view the next post <a href="[^baseurl]/posts/differential-exam-1.html">here</a>.</i>
+</p>
 <p>
     Welcome once more to Deadly Boring Math! With the tempestuous wight of Quiz 2 rapidly striding towards us (it's <i>tomorrow</i> in the usual studio time),
     I'm doing some last-minute studying, and figured I'd post some worked solutions here. These are by no means exhaustive; if you don't do your own studying,
@@ -30,7 +33,7 @@
 <p>
     The first step is to define some substitutions: `x = u`, `y = u'`, meaning `x' = u'`, and `y' = u''`. Note also that `x' = y`.
     Substituting these values into the equation gives us `y' - 2y + x = sin(t)`: because we have the constraint `x' = y`, this is
-    a system of equations. We do some algebra to get `y' = 2y - x + sin(t), x' = y`, which can be written in matrix form as `X' = \[\[0, 1], \[-1, 2]] X + [0, sin(t)]`.
+    a system of equations. We do some algebra to get `y' = 2y - x + sin(t), x' = y`, which can be written in matrix form as `X' = \[\[0, 1], \[-1, 2]] X + \[0, sin(t)]`.
 </p>
 <h2>WS3.3.1</h2>
 <p>
@@ -63,4 +66,5 @@
 [=title "Differential Quiz 2"]
 [=subject "Calculus"]
 [=author "Tyler Clarke"]
-[=date "2025-6-2"]
+[=date "2025-6-2"]
+[#post.html]